4x+5=x^2+27

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Solution for 4x+5=x^2+27 equation: 



4x+5=x^2+27

We move all terms to the left:

4x+5-(x^2+27)=0

We get rid of parentheses

-x^2+4x-27+5=0

We add all the numbers together, and all the variables

-1x^2+4x-22=0

a = -1; b = 4; c = -22;
Δ = b2-4ac
Δ = 42-4·(-1)·(-22)
Δ = -72
Delta is less than zero, so there is no solution for the equation

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